Perturbative unitarity for upper bound on the Higgs mass
TU Dortmund University
June 27, 2024
\[ \mathcal{L} = -\frac{1}{4}F_{\mu\nu}F^{\mu\nu} \;\;\;\;\;\;\;\; \text{with} \;\;\;\;\;\;\;\; F_{\mu\nu} = \partial_\nu A_\mu - \partial_\mu A_\nu \]
If mass term:
\[ +\frac{1}{2} m^2 A_{\mu} A^{\mu} \]
\(\mathcal{L}\) is invariant under:
Global \(U(1)\) rotations: \(\;\; A_{\mu}(x) \rightarrow e^{i\theta}A_{\mu}(x), \;\; \phi \rightarrow e^{i\theta} \phi\)
Local gauge transformations: \(\;\; A_\mu \rightarrow A_\mu - \partial_\mu \eta(x), \;\;\;\; \phi \rightarrow e^{-ie\eta(x)} \phi\)
The potential has two different forms:


Substitute \(\phi\) into \(\mathcal{L}\):
\[ \mathcal{L} = -\frac{1}{4} F_{\mu\nu} F^{\mu\nu} + |D_\mu \phi|^2 - V(\phi) \]
\[ \mathcal{L} = -\frac{1}{4} F_{\mu\nu} F^{\mu\nu} + \left( \frac{v + h}{\sqrt{2}} \right)^2 \left[ -i \frac{\partial_\mu \chi}{v} + \frac{\partial_\mu h}{v + h} - ie A_\mu \right] \left[ i \frac{\partial_\mu \chi}{v} + \frac{\partial_\mu h}{v + h} + ie A_\mu \right] - \left( \frac{\mu^4}{\lambda} + \mu^2 h^2 + \frac{1}{2} \sqrt{\lambda} \mu h^3 + \frac{1}{16} \lambda h^4 \right) \]
\[ \mathcal{L} = -\frac{1}{4} F_{\mu\nu} F^{\mu\nu} + \left( \frac{v + h}{\sqrt{2}} \right)^2 \left[ -i \frac{\partial_\mu \chi}{v} + \frac{\partial_\mu h}{v + h} - ie A_\mu \right] \left[ i \frac{\partial_\mu \chi}{v} + \frac{\partial_\mu h}{v + h} + ie A_\mu \right] - \left( \frac{\mu^4}{\lambda} + \mu^2 h^2 + \frac{1}{2} \sqrt{\lambda} \mu h^3 + \frac{1}{16} \lambda h^4 \right) \]
\[ \mathcal{L} = -\frac{1}{4} F_{\mu\nu} F^{\mu\nu} + \frac{1}{2} e^2 v^2 A_\mu^2 + \cdots \]
Gauge field \(A_\mu\) acquires a mass: \(\;\; m_A^2 = e^2v^2\)
\[ -\frac{\mu^4}{\lambda} - \mu^2 h^2 - \frac{1}{2} \sqrt{\lambda} \mu h^3 - \frac{1}{16} \lambda h^4 \]
The Higgs field \(h\) has a mass: \(\;\; m_h^2 = -2\mu^2\)
\[ \mathcal{L} = -\frac{1}{4} F_{\mu\nu}F^{\mu\nu} + \frac{1}{2} m_A^2 \left( A_\mu + \frac{1}{e v} \partial_\mu \chi \right)^2 \]
\[\begin{align*} A_\mu \rightarrow A_\mu' &= A_\mu - \frac{1}{e v} \partial_\mu \chi \\ \chi(x) &= 0 \end{align*}\]
Proca Lagrangian:
\[ \mathcal{L} = -\frac{1}{4} F_{\mu\nu}F^{\mu\nu} + \frac{1}{2} m_A^2 A_\mu A^\mu \]
\[ \phi \equiv \frac{1}{\sqrt{2}} e^{i \frac{\chi(x)}{v}} \left( v + h(x) \right) \]
Consequence:
The kinetic energy terms:
\[ \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad L = -\frac{1}{4}W^I_{\mu\nu}W^{I\mu\nu} - \frac{1}{4}B_{\mu\nu}B^{\mu\nu} \]
Coupled to the gauge fields the complex scalar \(SU(2)\) doublet \(\Phi = \begin{pmatrix} \phi^+ \\ \phi^0 \end{pmatrix}\)
The scalar potential is similar to the Abelian model: \[ V(\Phi) = \mu^2 |\Phi^{\dagger} \Phi| + \lambda (|\Phi^{\dagger} \Phi|)^2 \]
For \(\mu^2 < 0\), the VEV of \(\Phi\) is: \[ \langle \Phi \rangle = \frac{1}{\sqrt{2}} \begin{pmatrix} 0 \\ v \end{pmatrix} \]
With this choice the electromagnetig charge
\[ Q = \frac{(\tau_3 + Y)}{2} \;\;\; \text{with} \;\;\; Y_{\phi} = 1 \]
Scalar Contribution to the Lagrangian: \(\;\;\; \mathcal{L}_s = (D^\mu \Phi)^\dagger (D_\mu \Phi) - V(\Phi)\)
Covariant Derivative:
\[ D_\mu = \partial_\mu + i \frac{g}{2} \tau \cdot W_\mu + i \frac{g'}{2} B_\mu Y \]
In Unitary Gauge:
\[ M^2 \sim \frac{1}{2} (0, v) \left( \frac{1}{2} g \tau \cdot W_\mu + \frac{1}{2} g' B_\mu \right)^2 \begin{pmatrix} 0 \\ v \end{pmatrix} \]
\[\begin{align*} W^\pm_\mu &= \frac{1}{\sqrt{2}} (W^1_\mu \mp i W^2_\mu) \\[10pt] Z^\mu &= \frac{-g'B_\mu + g W^3_\mu}{\sqrt{g^2 + g'^2}} \equiv -\sin \theta_W B_\mu + \cos \theta_W W^3_\mu \\[10pt] A^\mu &= \frac{g B_\mu + g' W^3_\mu}{\sqrt{g^2 + g'^2}} \equiv \cos \theta_W B_\mu + \sin \theta_W W^3_\mu. \end{align*}\]
\[ M_W^2 = \frac{1}{4}g^2v^2 \quad \;\;\; M_Z^2 = \frac{1}{4}(g^2 + g'^2)v^2 \quad \;\;\; M_\gamma^2 = 0 \]
Electron Example:
\[ \;\;\; \mathcal{L}_e = -g_e \left[ \begin{pmatrix} \bar{\nu}_e & \bar{e} \end{pmatrix}_L \begin{pmatrix} \phi^+ \\ \phi^0 \end{pmatrix} e_R + \bar{e}_R \begin{pmatrix} \phi^{+*} & \phi^{0*} \end{pmatrix} \begin{pmatrix} \nu_e \\ e \end{pmatrix}_L \right] \\ \]
\[ \mathcal{L}_e = -\frac{g_e v}{\sqrt{2}} (\bar{e}_L e_R + \bar{e}_R e_L) - \frac{g_e}{\sqrt{2}} h (\bar{e}_L e_R + \bar{e}_R e_L) \]
Problem: Non-zero VEV is in the lower (neutral) component of the Higgs doublet.
Solution: constructing the conjugate doublet \(\;\; \phi_c \equiv i \tau_2 \phi^* = \begin{pmatrix} \phi^0 \\ -\phi^- \end{pmatrix}\)
\[ \mathcal{M} = 16\pi \sum_{l=0}^{\infty}(2l +1)a_l(|\vec{p}|)P_l(\cos\theta) \]
We obtain the result: \[ \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \sigma_{tot} = \frac{16\pi}{E^2_{CM}} \sum_{l=0}^{\infty}(2l +1)|a_l|^2 \]
The optical theorem states:
\[ \Im{\mathcal{M}(A \rightarrow A)} = 2E_{CM}|\vec{p}| \sum_{X} \sigma(A \rightarrow X) \geq 2E_{CM}|\vec{p}| \sigma(A \rightarrow A) \]
\[ \sum_{l=0}^{\infty}(2l + 1)\Im{a_l} = \frac{2|\vec{p}|}{E_{CM}} \sum_{l=0}^{\infty}(2l + 1)|a_l|^2 \] - Since \(\Im{a_l} \leq |a_l|\) in the high energy limit we have \(\Im{a_l} =Fina |a_l|\):
\[\begin{align} |a_l| \leq 1 \end{align}\]
\[\begin{align} |\Re{a_l}| \leq 1/2 \end{align}\]
\[\begin{align} 0 \leq |\Im{a_l}| \leq 1 \end{align}\]
For a vector with a momentum on the z-axis \(p^{\mu} = (E,0,0,p_z)\):
No energy dependence.
\[ \epsilon_{L} = \frac{1}{m}(p_z,0,0,E) \]
Energy dependence.
The vertex is: \(ig^2(2g_{\mu\sigma}g_{\nu\rho} - g_{\mu\nu}g_{\rho\sigma} - g_{\mu\rho}g_{\nu\sigma})\)
The energy-momentum 4 vectors:
The longitudinal polarization vectors:
\[\begin{aligned} &e_l(p_+)=\left(\frac{p}{M_W},0,0,\frac{E}{M_W}\right) \\ &e_l(k_+)=\left(\frac{p}{M_W},\frac{E}{M_W}\sin\theta,0,\frac{E}{M_W}\cos\theta\right) \\ &e_l(p_-)=\left(\frac{p}{M_W},0,0,-\frac{E}{M_W}\right) \\ &e_l(k_-)=\left(\frac{p}{M_W},-\frac{E}{M_W}\sin\theta,0,-\frac{E}{M_W}\cos\theta\right) \\ \end{aligned}\]\[ i\mathcal{M} \approx ig^2\frac{E^4}{M_W^4} \]
violates unitarity for high energies.
The Feynmann rule for the vertex is:
\[ i \left\{ \begin{array}{ll} e \\ g\cos\theta_W \\ \end{array} \right\} [g_{\mu\nu}(-p_- + p_+)_{\alpha} + g_{\mu\alpha}(q + p_+)_{\nu} + g_{\nu\alpha}(-q - p_-)_{\mu}] \]
The propagators are:
\[\begin{array}{cc} \frac{-i}{q^2 - M_Z^2} \left[g_{\alpha\beta} - \frac{q_{\alpha}q_{\beta}}{M_Z^2}\right] \quad \text{and} \quad & \frac{-ig_{\alpha\beta}}{q^2}\\ \end{array}\]We can get an estimate on the energy at which perturbative unitarity is violated.
The relation obtained before on \(\mathcal{M}\):
\[ \mathcal{M}=16\pi\sum_{J=0}^{\infty}(2J+1)a_JP_J(\cos\theta) \] \[ \int_{-1}^{1}P_J(\cos \theta)d(\cos \theta) \mathcal{M} = 16\pi\sum_{l=0}^{\infty}(2J+1)a_J\int_{-1}^{1}P_J(\cos \theta)P_J(\cos \theta)d(\cos \theta) \]
\[ \int_{-1}^{1} d(\cos \theta) \, P_J(\cos \theta) P_{J'}(\cos \theta) = \frac{2}{2J + 1} \delta_{JJ'} \]
The propagator is: \[ \frac{-i}{q^2 - m_h^2} \left[g_{\alpha\beta} - \frac{q_{\alpha}q_{\beta}}{m_h^2}\right] \] The Feynmann rule for the verteces is: \[ \frac{2iM_W^2g_{\mu\nu}}{v}=i\frac{g^2v}{2}g_{\mu\nu} \]
We obtain a contribution of: \[ i\mathcal{M_h} = -i\frac{i}{v^2}\left(\frac{s^2}{s-m_h^2} + \frac{t^2}{t-m_h^2}\right) \]
Taylor expanding for \(s,t >> m_h^2\) we have: \[ i\mathcal{M_h} \simeq -i\frac{1}{v^2}(s+t+2m_h^2) \]
Summing the contributions, we see the energy dependent term cancel: \[ i\mathcal{M} \simeq -i\frac{1}{v^2}(2m_h^2) \]
Using previous relation for a_0: \[ a_0(s) = \frac{1}{32 \pi} \int_{-1}^{1} d(\cos \theta) \, \mathcal{M}(s, \cos \theta) \] \[ a_0 \simeq -\frac{1}{16\pi v^2}(2m_h^2) \]
Applying \(|\Re{a_0}| < 1/2\) we finally obtain an upper bound on the Higgs boson mass. \[ m_h^2 \leq 4\pi v^2 \simeq (870 GeV)^2 \]
Let’s start from an incoming plane wave propagating in the z direction: \[ \psi(\vec{r}) = e^{ik \cdot \vec{r}} = e^{ikr\cos\theta} \]
rewritten in terms of the spherical Bessel functions and the Legendre polynomials: \[ \psi(\vec{r}) = \sum_{l=0}^{\infty}(2l +1)(i)^l j_l(kr)P_l(\cos\theta) \]
\[ \psi(\vec{r}) \simeq \frac{i}{2k}\sum_{l=0}^{\infty}(2l +1)(i)^l \left[\frac{e^{-i(kr - l\pi/2)}}{r} - S_l(k)\frac{e^{+i(kr - l\pi/2)}}{r} \right]P_l(\cos\theta) \]
\[ f(\theta) = \frac{1}{k}\sum_{l=0}^{\infty}(2l +1)a_l(k)P_l(\cos\theta) \]
\[ a_l(k) = \frac{S_l(k)-1}{2i} \]